2x^2+32x-64=1080

Solution for 2x^2+32x-64=1080 equation:

2x^2+32x-64=1080

We move all terms to the left:

2x^2+32x-64-(1080)=0

We add all the numbers together, and all the variables

2x^2+32x-1144=0

a = 2; b = 32; c = -1144;
Δ = b2-4ac
Δ = 322-4·2·(-1144)
Δ = 10176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10176}=\sqrt{64*159}=\sqrt{64}*\sqrt{159}=8\sqrt{159}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8\sqrt{159}}{2*2}=\frac{-32-8\sqrt{159}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8\sqrt{159}}{2*2}=\frac{-32+8\sqrt{159}}{4}
$